find the area and perimeter of a square whose diagonal is 7√2 cm long
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Given
We have given diagonal of square is 7√2cm
To Find
we have to find area and perimeter of square
If diagonal of square is given and we have to find area then apply this formula:
Area of square=1/2d²
Area of square= (7√2)²÷2
Area of square= 49×2÷2
Area of square= 98÷2
Area of square=49cm²
Now ,we know that area of square is (side)²
=>(side)²=49
=>side =√49
=>side =7cm
We have side of square= 7cm
and we know that all sides of square are equal.
So, perimeter of square= 4×side
=>Perimeter of square= 4× 7cm= 28cm
Perimeter of square= 28cm
Area of square= 49cm²
Extra information=>
Properties of Square:
- A square is a quadrilateral having 4 sides & 4 vertices.
- All sides of a square are equal.
- Opposite sides of a square are parallel.
- The diagonals of a square bisects each and makes an angle of 90°
- The sum of square of Diagonals is greater than the sum of square of their sides.
- The Diagonals are also equal.
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