Question

Find the area and perimeter of the rectangle whose length is 8 cm and breadth is 6 cm

Answer 1

Answer:

Step-by-step explanation:

l=8cm

b=6cm

perimeter of rectangle=2(l+b)

                                     =2(8+6)

                                     =2x14

                                     =28cm

area of rectangle=lxb

                            =8x6

                            =48cm^2

Answer 2

The area of the rectangle is 48 cm².

The perimeter of the rectangle is 28 cm.

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Let's understand a few concepts:

To calculate the area of the rectangle we will use the following formula:

$\boxed{\bold{Area \:of\: rectangle = length \times breadth}}$

To calculate the perimeter of the rectangle we will use the following formula:

$\boxed{\bold{Area \:of\: perimeter = 2[length + breadth]}}$

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Let's solve the given problem:

The dimensions of the given rectangle :

Length = 8 cm

Breadth = 6 cm

Area of rectangle:

By using the above formula of the area of a rectangle, we get

The area of the rectangle is,

= length × breadth

= 8 cm × 6 cm

= 48 cm²

Perimeter of rectangle:

By using the above formula of the perimeter of a rectangle, we get

The perimeter of the rectangle is,

= 2× [length + breadth]

= 2 × [8 cm + 6 cm]

= 28 cm

Thus, the area and perimeter of the rectangle is 48 cm² and 28 cm respectively.

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