Question

Find the area and the perimeter of a rectangle whose length is 20cm and breadth is 12 cm.?​

Answer 1

Step-by-step explanation:

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Answer 2

Question:-

Find the area and the perimeter of a rectangle whose length is 20cm and breadth is 12 cm.?

Required Answer:-

Given:-

• Length of the rectangle = 20cm
• Breadth of the rectangle = 12cm

To Find:-

• Area of the rectangle
• Perimeter of the rectangle

♡Solution:-

First, we have to know that:-

$\\ \underline{ \boxed{ \pmb{Area \: of \: a \: rectangle = length \times bredth \: sq.units}}}$

As we were given,

• Length of the rectangle = 20cm
• Breadth of the rectangle = 12cm

Substituting the values we find:-

$\\ \sf{Area \: of \: the \: rectangle = \bold{20cm \times 12cm}}$

$\sf{ \rightarrow{Area \: of \: the \: rectangle = \bold{(20\times 12) {cm}^{2} }}}$

$\sf{ \therefore{Area \: of \: the \: rectangle = \bold{ \red{240 {cm}^{2} }}}}$

Again,

$\\ \underline{ \boxed{ \pmb{Perimeter \: of \: a \: rectangle = 2(length + breadth)units}}}$

Therefore,

$\\ \sf{Perimeter \: of \: the \: rectangle = \bold{2(12cm + 20cm)}}$

$\sf{ \rightarrow{Perimeter \: of \: the \: rectangle = \bold{2(12 + 20)cm}}}$

$\sf{ \therefore{Perimeter \: of \: the \: rectangle = \bold{ \red{64cm}}}}$

$\\ \\ \underline{ \boxed{ \rm{Hence, \: area \: of \: the \: rectangle \: is \: \bold{240 {cm}^{2} } \: and \: perimeter \: is \: \bold{64cm}}}}$