find the area bounded by the parabola y^2=4x and y^2=4 - 4x
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Intersection point of the curves y2=4x and y=x
are (0,0) and (1,2)
Area of the the shaded region is given by:
A=∫02y−4y2
⇒A=[2y2]02−[12y3]02
⇒A=2−32=34 sq. units
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