Question

Three sides of a triangle are 3a2 - 2a + 5, a2
+8, and 4a²-a- 5. Find the perimeter of the
triangle​

Answer 1

we have the value of all the vertices of the triangle hence the sum of it will be perimeter of triangle i.e. 3a2-2a+5+a2+8+4a^2-a-5=4a^2+5a+8 this will be perimeter of triangle please give me thanks and make me branilist