Question

Find the area covered by a roadroller in 50 revolutions if its diameter is 140 cm and its width is
20 cm. Convert the area into m2​

Answer 1

$\huge \boxed{\red{\mathfrak{Given:-}}}$

• Diameter of the roadroller = 140 cm
• Width of the roadroller = 20 cm

$\huge \boxed{\red{\mathfrak{To \: find :-}}}$

• Area covered by the roadroller in 50 revolutions in m²

$\huge \boxed{\red{\mathfrak{Solution:-}}}$

As we know that,

$\rm r = \frac{d}{2}$

Therefore,

=> r = 140/2

=> r = 70 cm = 0.7 m

Also,

Width = height = 20 cm = 0.2 m

Now,

Hence, Roadroller is of the Cylindrical shape.

As we know that,

$\large{\boxed{\red{\mathrm{C.S.A \ of \ Cylinder \ = 2 \pi r h}}}}$

Therefore,

$\therefore \rm 2 \times \frac{22}{7} \times 0.7 \times 0.2$

$\implies \rm 2 \times \frac{22}{7} \times 0.14$

$\implies \rm 2 \times 22 \times 0.02$

$\implies \rm \bf \blue{0.88m^2}$

Now,

So, area covered by the roadroller on the road in 50 revolutions is,

$\rm \therefore 0.88m^2 \times 50$

$\rm \implies \bf \blue{ 44m^2}$

Hence, the area covered by the roadroller in 50 revolutions is 44m²