find the area enclosed by each of the following figure (take π = 3.14)
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Answer:
Area = area of □AEDC+ area of △ABC [ref. image (i)]
=4×4+21×4×2
=16+4=20cm2
(ii) Area = are of trapezium DEFC+ area of □ABCF [ref. image (ii)]
=28×(7+18)+18×18
=4×25+18×18
=100+324
=424cm2
(iii) Area = area of trapezium EDAF+ area of □ABCD [ref. image (iii)]
=28×(6+20)+20×20
=4×26+400
=104+400
=504cm2
Step-by-step explanation:
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Step-by-step explanation:
area of semicircle => 1/2 x π r^2
=> 1/2 x 3.14 x 10^2
=> 1/2 x 314/100 x 100
=> 1/2 x 314
=> 157cm^2 :)
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