Question

find the area enclosed by the given figure a b c d e f as per dimension given herewith

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

The area enclosed by the figure is $\bf =400+104=504 cm^2$.

Given:

A square AFCB of side length 20 cm

A trapezium FCED on top of that with ED = 6 cm, FC = 20 cm, and its height is 8 cm.

To Find:

The area enclosed by the figure

Solution:

We can find the total area as the sum of the area of the square and the trapezium.

The area of the square is given by

$a^2=20^2=400 cm^2$

The area of the trapezium is given by

$\frac{1}{2}*h*[d_1+d_2] =\frac{1}{2}*8*[6+20]=104 cm^2$

Hence, the Total Area is $\bf =400+104=504 cm^2$.

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