Question

Find the area enclosed by this figure​

Answer 1

Answer:

idk sry

Step-by-step explanation:

Answer 2

Answer:

316cm²

Step-by-step explanation:

First the area of the rectangle

length=14cm , breath=8cm

Area of the rectangle=L×B =14×8

=112cm²

Now, the area of trapeziumhere, a=8cm , b=16cm , h=25-8/2 =8.5

{note:here a and b are the parallel sides of trapezium.}

Area of trapezium=1/2×(a+b)×h =1/2×(8+16)×8.5 =1/2×24×8.5

=12×8.5

=102cm²

here, both the trapezium are equal so, the area of other trapezium is also 102cm²

area of both the trapezium=102+102 =204cm²

Area of the figure=Area of both trapezium+Area of the rectangle = 204+112

=316cm²

therefore, the area of the figure is 316cm²