Question

Find the area (in cm2 )of the shaded region.

Answer 1

The area of rectangle = (5x6) cmsq.
=30cm.sq.
The area shaded region=
ar(rectangle) - [ 2ar(corner triangle) + ar(smaller triangle)]
$= 30 - 2(\frac{1}{2} \times 5 \times 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - ( \frac{1}{2} \times 6 \times 2) \\ = 30 - (5 \times 3) - (6) \\ = 30 - 15 - 6 \\ = 30 - 21 = 9cmsq.$
Therefore the required area is 9 sq. cm.
The altitude of the corner triangle is the breadth of rectangle and base equals half the length of rectangle. Where as the altitude of the smaller triangle is the line from it's upper vertex to its base and the base is the length of the rectangle.
Hope it's clear Please Mark it as the brainliest.

Answer 2

Hey bro !!

Here is the solution...

Area of Shaded Region = Area of ◻ABCD rectangle - Area of ∆AMD - Area of ∆BMC - Area of ∆NDC

Area of ◻ ABCD = AD × DC
= 5 × 6
= 30 cm^2

Area of ∆AMD = 1/2 × AD × AM
= 1/2 × 5 × 3
= 15/2
= 7.5 cm^2

Area of ∆BMC = 1/2 × BC × BM
= 1/2 × 5 × 3
= 15/2
= 7.5

Area of ∆NDC = 1/2 × NO × DC
= 1/2 × 2 × 6
= 6 cm^2


Area of Shaded Region = 30 - 7.5 - 7.5 - 6
= 30 - 21
= 9 cm^2


HOPE IT HELPS YOU....

THANKS
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