Find the area in square metres, of the triangle
whose base and altitude are as under:
(a) base = 22 dm and altitude = 10 dm
(b) base = 65 cm and altitude = 20 cm
(c) base = 10 m and altitude = 70 cm
(d) base = 1200 cm and altitude = 90 dm
please tell me answer
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Answer:
1 dm = 0.1 m
1 cm = 0.01 m
Area of Triangle = 1/2 × base × altitude
(a) Area = 1/2 × 22 dm × 10 dm
= 1/2 × 2.2 m × 1 m
= 2.2/2 = 1.1 m²
Area = 1.1 m²
(b) Area = 1/2 × 65 cm × 20 cm
= 1/2 × 0.65 m × 0.2 m
= 0.65 × 0.1 = 0.065 m²
Area = 0.065 m²
(c) Area = 1/2 × 10 m × 70 cm
= 1/2 × 10 m × 0.7 m
= 1/2 × 7 = 3.5 m²
Area = 3.5m²
(d) Area = 1/2 × 1200 cm × 90 dm
= 1/2 × 12 m × 9 m
= 6 × 9 = 54 m²
Area = 54 m²
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