find the area in terms of 1/2*b*h
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In ∆ABD,
AB² - BD² = AD²
=> 6² - 4² = 36 - 16 = 20
=> AD = √20 = 2√5 units
Area of ∆ABC
=> 1/2 × 4 × 2√5 = 4√5 units²
AB² - BD² = AD²
=> 6² - 4² = 36 - 16 = 20
=> AD = √20 = 2√5 units
Area of ∆ABC
=> 1/2 × 4 × 2√5 = 4√5 units²
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