Question

Find the area (in unit square) of region bounded by x = 4, x + y = 6 and coordinate axes​

Answer 1

Answer:

coordinate axis is( 4,2).

x=4,x+y=6

4+y=6

y=2

Answer 2

Answer:

The total area of the region bounded by x = 4, x + y = 6 and coordinate axes​ is 16 unit square.

Step-by-step explanation:

x = 4, x + y = 6,x=0 , y=0 are the four boundary for the region.

Let the line x + y = 6 intersect x = 4 at point B and it intersects y-axis at D.

Coordinate of B is (4,2) [See the picture attached].

Coordinate of D is (0,6).

O is the point representing(0,0).

Line x = 4 intersects x-axis at A(4,0).

According to the diagram, area of OABD = area of OABC + area of BCD

= OA × AB + $\frac{1}{2}$×BC×CD = 4×2 + $\frac{1}{2}$×4×4 = 8+8 = 16 unit square.

Hence, the total area of the region bounded by x = 4, x + y = 6 and coordinate axes​ is 16 unit square.