Find the area isosceles triangle ABC in which AB=AC
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Step-by-step explanation:
Let the equal sides of isosceles triangle be a.
and other is x
then,
construct the median AD
AD divides BC into two equal parts
Area of isosceles triangle =
½ [ x ✖ √a^2 - x^2/4 ]
½ [ 10 ✖ √ 36 - 100 / 4 ]
½ [ 10 ✖ √144 - 100 /4 ]
½ [ 10 ✖ ½ √ 44 ]
½ [ 5 ✖ √ 2 ✖ 2 ✖ 11 ]
½ [ 5 ✖ 2 √11 ]
½ [10 √11 ]
5√11 cm square is the area of isosceles
triangle
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