Math, asked by anandraj9118, 8 months ago

Find the area isosceles triangle ABC in which AB=AC​

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Answered by prathamesh352
0

Answer:

follow the attachment

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Answered by siyq65
0

Step-by-step explanation:

Let the equal sides of isosceles triangle be a.

and other is x

then,

construct the median AD

AD divides BC into two equal parts

Area of isosceles triangle =

½ [ x ✖ √a^2 - x^2/4 ]

½ [ 10 ✖ √ 36 - 100 / 4 ]

½ [ 10 ✖ √144 - 100 /4 ]

½ [ 10 ✖ ½ √ 44 ]

½ [ 5 ✖ √ 2 ✖ 2 ✖ 11 ]

½ [ 5 ✖ 2 √11 ]

½ [10 √11 ]

5√11 cm square is the area of isosceles

triangle

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