find the area of 10 sheeting required for making an open system without a lead 5m long 3M wide and 4 m Deep
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Hi Given measurements,
length=5m
width=3m
deep=4m
T.S.Aof rectangle=2(lb+BH+HL)
=>2(5*3+3*4+4*5)
=>2(15+12+20)
=>2(47)
=>94m²
Hence, area of 10 sheet required= 94m².
=10 *94 =940
Hope this helpful.
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length=5m
width=3m
deep=4m
T.S.Aof rectangle=2(lb+BH+HL)
=>2(5*3+3*4+4*5)
=>2(15+12+20)
=>2(47)
=>94m²
Hence, area of 10 sheet required= 94m².
=10 *94 =940
Hope this helpful.
Mark it as branliest if you find it useful.
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