Question

Find the area of a ∆CAB with angle ACB = 120° & CA = CB = 18 cm​

Answer 1

Answer:

81* square root of 3

Step-by-step explanation:

Answer 2

So here is your answer bro

We have triangle with angle on top =120° and it is a isosceles triangle I.e. Each side has 18 cm length so here angle A and angle B are equal to 60 degree ..

And line CM is acting as bisector so Angle MCB is equal to 60degreee and hence ot is forming an equilateral triangle

So area = √3/4 × 18

4.5√3 is the answer

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