Question

Find the area of a cyclic quadrilateral whose sides are 8cm, 10cm, 12cm & 16 cm.

Answer 1

area = √(s-a)(s-b )( s-c)(s-d ) for cylic quadrilateral
s = half of perimeter of quadrilateral of. side lengths a,b,c,d= 46/2 = 23

Answer 2

Answer:

$122.535 cm^2$

Step-by-step explanation:

a= 8 cm

b = 10 cm

c = 12 cm

d = 16 cm

Area of cyclic quadrilateral = $\sqrt{(s-a)(s-b)(s-c)(s-d)}$

Where $s=\frac{a+b+c+d}{2}$

So,  $s=\frac{8+10+12+16}{2}$

 $s=23$

Area of cyclic quadrilateral = $\sqrt{(23-8)(23-10)(23-12)(23-16)}$

Area of cyclic quadrilateral = $122.535 cm^2$

Hence Area of cyclic quadrilateral is $122.535 cm^2$