Find the area of a isosceles triangle each of whose equal side is 13cm and whose base is 24cm
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Let ∆ABC is an isosceles triangle.
In which,
AB = AC = 13 cm
And,
BC= 24 cm
Therefore,
Area of triangle ABC = 1/4 ×B under root4A²-B²
=> 1/4 × 24 × under root 4 × (13)² - (24)²
=>[ 1/2 × 24 × under root 4 × 169 - 24 × 24] cm²
=> [ 1/4 × ( 676 - 576)]
=> 6 × rot 100
=> 6 × 10
=> 60 cm²
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
Let ∆ABC is an isosceles triangle.
In which,
AB = AC = 13 cm
And,
BC= 24 cm
Therefore,
Area of triangle ABC = 1/4 ×B under root4A²-B²
=> 1/4 × 24 × under root 4 × (13)² - (24)²
=>[ 1/2 × 24 × under root 4 × 169 - 24 × 24] cm²
=> [ 1/4 × ( 676 - 576)]
=> 6 × rot 100
=> 6 × 10
=> 60 cm²
★ ★ ★ HOPE IT WILL HELP YOU ★ ★ ★
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