Math, asked by wwqddq, 8 months ago

find the area of a isosceles triangle whose base is 16cm and one of its equal side is 10cm

Answers

Answered by mandeep7777
1

Answer:

Base = 16 cm.

Length of both equal sides = 10cm.

Heron's formula

Side 1, a = 16 cm.

Side 2, b = 10 cm.

Side 3, c = 10 cm.

Therefore,

Half perimeter= s = 1/2×(16+10+10)

= 36/2

s = 18 cm.

Hence, the area of given triangle is 48 cm².

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