find the area of a isosceles triangle whose base is 16cm and one of its equal side is 10cm
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Answer:
Base = 16 cm.
Length of both equal sides = 10cm.
Heron's formula
Side 1, a = 16 cm.
Side 2, b = 10 cm.
Side 3, c = 10 cm.
Therefore,
Half perimeter= s = 1/2×(16+10+10)
= 36/2
s = 18 cm.
Hence, the area of given triangle is 48 cm².
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