Math, asked by ray654, 1 year ago

Find the area of a parallelogram ABCD in which AB=14cm,BC=10cm and AC=16cm

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Answered by nithilan
6
ab =cd=14cm(in parallelogram opposite
BC=ad=10cm. sides are equal)
ar(ABC)=ar(ACD)(same base lies b/w same parallel therefore it's areas are equal)
ar(ABCD)=ar(ABC)+ar(ACD)
=2ar(ABC)
ar(ABCD)=b*h
=14*10=140

ray654: how is the base 14 and height 10
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