Question

find the area of a parallelogram in which ab=14cm,bc=10cm,and ac=16​

Answer 1

Step-by-step explanation:

In △ ABC Take a = 10cm, b = 16cm and c = 14cm So we get

by using herons formula,

s=a+b+c/2

area of triangle abc =

$40 \sqrt{3}$

We know that a diagonal in a parallelogram divides it into two equal area

So we get Area of parallelogram ABCD = Area of △ ABC + Area of △ ACD

It can be written as Area of parallelogram ABCD = 2(Area of △ ABC)

By substituting the values Area of parallelogram ABCD = 2 (40 √3)

So we get Area of parallelogram ABCD = 80√3

By substituting √3

Area of parallelogram ABCD = 80 (1.73)

So we get Area of parallelogram ABCD = 138.4 cm2

Therefore, the area of parallelogram ABCD is 138.4 cm2.

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