Question

Find the area of a parallelogram PQRS given alongside. Also, find the distances between pq and rs.

Answer 1

Area of parallelogram is $\mathbf{24(m^{2})}$ and distance between PQ and RS is 3 m, while distance PS and QR is 4 m.

Step-by-step explanation:

1. Given data

  PQ = 8 m

  PS = 6 m

2. Let altitude at PQ $\mathbf{(h_{1})=3 m}$

   and altitude at PS$\mathbf{=(h_{2})}$

3. Area of parallelogram of PQRS

   Area of PQRS $\mathbf{= side \times altitude}$

   which can be write as

   Area of PQRS  $\mathbf{= 8 \times 3=24 m^{2}}$

4. Area of parallelogram PQRS in terms of side PS can be written as

   Area of PQRS= 24

   $\mathbf{6 \times h_{2}=24 m^{2}}$

   So

   $\mathbf{h_{2}=4 m}$ = distance between side PS and QR

Answer 2

Answer:

Area of parallelogram is \mathbf{24(m^{2})}24(m

2

) and distance between PQ and RS is 3 m, while distance PS and QR is 4 m.

Step-by-step explanation:

1. Given data

PQ = 8 m

PS = 6 m

2. Let altitude at PQ \mathbf{(h_{1})=3 m}(h

1

)=3m

and altitude at PS\mathbf{=(h_{2})}=(h

2

)

3. Area of parallelogram of PQRS

Area of PQRS \mathbf{= side \times altitude}=side×altitude

which can be write as

Area of PQRS \mathbf{= 8 \times 3=24 m^{2}}=8×3=24m

2

4. Area of parallelogram PQRS in terms of side PS can be written as

Area of PQRS= 24

\mathbf{6 \times h_{2}=24 m^{2}}6×h

2

=24m

2

So

\mathbf{h_{2}=4 m}h

2

=4m = distance between side PS and QR