Question

find the area of a parallelogram PQRS,if PR=24cm and QU=St=8cm​

Answer 1

Answer:

hey there

ar (llgm PQRS) = ar (∆ PQR) + ar (∆ PSR)

= 2× (1/2 × base × height)

= 24 × 8

= 192cm sq

Hence, area of parallelogram is equal to 192 sq cm

hope it helps you

Answer 2

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PR = 24 cm

ST = 8 cm

Area of ∆ PRS →

→$\frac{1}{2}\times b \times h$

→$\frac{1}{2}\times 24 \times 8$

→$96\:cm^{2}$

Area of ∆ PRQ →

→$\frac{1}{2}\times b \times h$

→$\frac{1}{2}\times 24 \times 8$

→$96\:cm^{2}$

Area of parallelogram PQRS →

→ Area of ∆ PRS + Area of ∆ PRQ

→$96\:cm^{2}+96\:cm^{2}$

→$192\:cm^{2}$

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