Find the area of a quadrant of a circle whose circumeference is 22 cm.
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area of quadrant = 1/4 area of circle.2pir=22 pi r = 11.r= 11/pi.1/4.pi 121/pi^2. 121/4 pi.is the answer
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2πr=22⟹r=11π2πr=22⟹r=11π
hence the area of circle is
=πr2=π(11π)2=121π=πr2=π(11π)2=121π
≈38.51549623 cm2