find the area of a quadrant of a circle whose circumference is 44cm
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Answered by
7
Circumference of quadrant =44
![(1 \div 4) \times 2\pi \: r = 44 (1 \div 4) \times 2\pi \: r = 44](https://tex.z-dn.net/?f=%281+%5Cdiv+4%29+%5Ctimes+2%5Cpi+%5C%3A+r+%3D+44)
r=22×4/pi
r = 28cm
area if a quadrant if a circle =
![(1 \div 4)\pi {r}^{2} (1 \div 4)\pi {r}^{2}](https://tex.z-dn.net/?f=%281+%5Cdiv+4%29%5Cpi+%7Br%7D%5E%7B2%7D+)
=1/4×pi ×28×28
=28×7 pi
=28 × 7 ×22/7
![616 {cm}^{2} 616 {cm}^{2}](https://tex.z-dn.net/?f=616+%7Bcm%7D%5E%7B2%7D+)
r=22×4/pi
r = 28cm
area if a quadrant if a circle =
=1/4×pi ×28×28
=28×7 pi
=28 × 7 ×22/7
Answered by
5
Hey friend, Harish here.
Here is your answer:
Given that,
Circumference of the circle = 44cm
To find,
Area of the circle.
Solution,
We know that,
![Circumference = 2 \pi r Circumference = 2 \pi r](https://tex.z-dn.net/?f=Circumference+%3D+2+%5Cpi+r)
→![44 = 2\times \frac{22}{7} \times r 44 = 2\times \frac{22}{7} \times r](https://tex.z-dn.net/?f=44+%3D+2%5Ctimes++%5Cfrac%7B22%7D%7B7%7D+%5Ctimes+r)
→![r = \frac{44\times 7}{44 } r = \frac{44\times 7}{44 }](https://tex.z-dn.net/?f=r+%3D++%5Cfrac%7B44%5Ctimes+7%7D%7B44+%7D+)
→![r = 7\ cm r = 7\ cm](https://tex.z-dn.net/?f=r+%3D+7%5C+cm)
Then,
![Area \ of\ circle= \pi r^{2} Area \ of\ circle= \pi r^{2}](https://tex.z-dn.net/?f=Area+%5C+of%5C+circle%3D++%5Cpi+r%5E%7B2%7D)
→![\frac{22}{7} \times 7 \times 7 \frac{22}{7} \times 7 \times 7](https://tex.z-dn.net/?f=+%5Cfrac%7B22%7D%7B7%7D+%5Ctimes+7+%5Ctimes+7)
→![22\times 7 22\times 7](https://tex.z-dn.net/?f=22%5Ctimes+7)
→![154\ cm^{2} 154\ cm^{2}](https://tex.z-dn.net/?f=154%5C+cm%5E%7B2%7D)
Therefore area of the circle is 154cm².
__________________________________________________
Hope my answer is helpful to you.
Here is your answer:
Given that,
Circumference of the circle = 44cm
To find,
Area of the circle.
Solution,
We know that,
→
→
→
Then,
→
→
→
Therefore area of the circle is 154cm².
__________________________________________________
Hope my answer is helpful to you.
Rahul1301:
we have to find area of quadrant
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