Question

find the area of a quadrant of a circle whose circumference is 44cm

Answer 1

Circumference of quadrant =44
$(1 \div 4) \times 2\pi \: r = 44$
r=22×4/pi
r = 28cm

area if a quadrant if a circle =
$(1 \div 4)\pi {r}^{2}$
=1/4×pi ×28×28
=28×7 pi
=28 × 7 ×22/7
$616 {cm}^{2}$

Answer 2

Hey friend, Harish here.

Here is your answer:

Given that,

Circumference of the circle = 44cm

To find,

Area of the circle.

Solution,

We know that,

$Circumference = 2 \pi r$

→  $44 = 2\times \frac{22}{7} \times r$

→ $r = \frac{44\times 7}{44 }$

→ $r = 7\ cm$

Then,

$Area \ of\ circle= \pi r^{2}$

→ $\frac{22}{7} \times 7 \times 7$

→ $22\times 7$

→ $154\ cm^{2}$

Therefore area of the circle is 154cm².
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Hope my answer is helpful to you.