Question

Find the area of a quadrilateral 2 points
whose one diagonal is 9cm and
the sum of perpendiculars from
opposite vertices on it is 12 cm.​

Answer 1

Answer:

yhwhs gwuw/5,95

acagva

Step-by-step explanation:

hauhw

ggsiiab

fsghs

/5*665

fhaje

gwhsis

Answer 2

Step-by-step explanation:

Given ABCD is a quadrilateral with AC=20cm and BP=9cm & OD=15cm and BP⊥AC & OD⊥AC

area of ΔABC=

2

1

×AC×BP=

2

1

×20×9=90cm

2

[Area of ΔABC−90cm

2

]

Area of ΔADC=

2

1

×AC×OD=

2

1

×20×15=150cm

2

Area of [ΔADC=150cm

2

]

Area of quadrilateral =area of ΔADC+ area of Δ ABC

=90+150

Area of quadrilateral (ABCD)=240cm

2

Hence area of quadrilateral ABCD is 240cm

2

.