Question

Find the area of a quadrilateral ABCD in which AB= 3 cm, BC= 4 cm, CD= 4 cm, DA= 3 cm

and AC = 6cm.​

Answer 1

Answer:

12cm² .

Step-by-step explanation:

Given,

AB =3cm , BC=4cm, CD=4cm, DA=3cm.

Area = length*breadth (as it is a rectangle)

Area = 4cmx 3cm

= 12cm².

Answer 2

Answer :-

• Area of quadrilateral ABCD = 12 cm²

Given :-

• AB = 3 cm
• BC = 4 cm
• CD = 4 cm
• DA = 3 cm
• AC = 6 cm

To Find :-

• Area of quadrilateral ABCD = ?

Explanation :-

By the given Information and by my attachment, we can find the area of quadrilateral ABCD by Finding the area of Triangle ABC and Triangle ADC.

$\green { \boxed { \bf \bigstar \: Area \: of \: ABCD = Area \: of \: ABC + Area \: of \: ADC  \: \bigstar }}$

_____________________

Finding the Area of both Triangles

NOTE - Both Triangles have Same Dimensions. Hence, their Area will be same :)

$\green { \boxed { \bf \bigstar \: Area \: of \: Triangles \: ABC \: and \: ADC = (\dfrac{1}{2} \times B \times H) \times 2 \: \bigstar }}$

$\rm : \: \leadsto (\dfrac{1}{2} \times B \times H) \times 2 = Area \: of \: Both \: Triangles$

$\rm : \: \leadsto (\dfrac{1}{2} \times 4 \times 3) \times 2$

$\rm : \: \leadsto (1 \times 2 \times 3) \times 2$

$\rm : \: \leadsto 6 \times 2$

$\blue { \underline { \boxed { \bf : \: \leadsto 12 \: cm^2 }}}$

$\pink { \boxed { \bf \bigstar \: Area \: of \: ABCD = Area \: of \: Both \: Triangles \: \bigstar }}$

$\red { \underline { \boxed { \bf : \: \leadsto Area \: of \: Quadrilateral \: ABCD = 12 \: cm^2 }}}$

Hence, the area of the Quadrilateral ABCD is 12 cm²