Math, asked by negideepti97, 4 months ago

find the area of a quadrilateral abcd in which diagonal =15cm and length of perpendiculars from b and d on ac are 3 cm and 5cm respectively

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

the diagonal divide the quadrilateral into 2 triangles

∆ABC and ∆ADC

area of ∆ABC = 1/2 × AC × h

= 1/2 × 15 × 3

= 7.5 × 3

= 22.5 sq cm

area of ∆ADC = 1/2 × AC × h

= 1/2 × 15 × 5

= 7.5 × 5

= 37.5 sq cm

area of quadrilateral ABCD

= ar ∆ ABC + ar ∆ ADC

= 22.5 + 37.5

= 60 sq cm

Answered by Anonymous
0

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