find the area of a quadrilateral abcd in which diagonal =15cm and length of perpendiculars from b and d on ac are 3 cm and 5cm respectively
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Answer:
Step-by-step explanation:
the diagonal divide the quadrilateral into 2 triangles
∆ABC and ∆ADC
area of ∆ABC = 1/2 × AC × h
= 1/2 × 15 × 3
= 7.5 × 3
= 22.5 sq cm
area of ∆ADC = 1/2 × AC × h
= 1/2 × 15 × 5
= 7.5 × 5
= 37.5 sq cm
area of quadrilateral ABCD
= ar ∆ ABC + ar ∆ ADC
= 22.5 + 37.5
= 60 sq cm
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