Question

find the area of a quadrilateral ABCD of Ab=10cm BC=12cm CD=8cm AD=6cm and diagonal AC=14cm.​

Answer 1

Answer:

Step-by-step explanation:

AB=10cm   BC=12cm    CD=8cm    AD=6cm

Diagonal of quadrilateral = AC= 14cm

let us take ΔABC and ΔADC

Now, area of ΔABC will be

by heron's formula = √s(s-a)(s-b)(s-c)

here, s= a+b+c÷2

s= 10+12+14/2

s=18

area of triangle = √18(18-10)(18-12)(18-14)

48cm²

Now, area of ΔADC will be

√s(s-a)(s-b)(s-c)

s= a+b+c/2

s=6+8+14/2

s=14cm

area of ΔADC = √14(14-14)(14-8)(14-6)

=0cm²

add the area of triangle ABC and triangle ADC

=48cm²+ 0cm²

=48cm²