find the area of a quadrilateral ÀBCD which has diagonal 10 m and perpendicular on it form opposite vertices are 6 m 5 m
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area of triangle with perpendicular of 6m
area = 1/2 × 6 × 10
area 1 = 30cm^2
area of triangle with perpendicular 5 m
area 2 = 1/2 × 5 × 10
area 2 = 25cm^2
area quadrilateral = area 1 + area 2
= 30 + 25
=55cm^2
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area = 1/2 × 6 × 10
area 1 = 30cm^2
area of triangle with perpendicular 5 m
area 2 = 1/2 × 5 × 10
area 2 = 25cm^2
area quadrilateral = area 1 + area 2
= 30 + 25
=55cm^2
plz make it brainliest and follow me llz
anurag0804rathore:
plz make it brainliest
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