find the area of a quadrilateral in which AB = 9cm ,BC=40cm ,CD=28cm ,DA=15cm and ANGLE AB = 90 degree
ritvikjain2090ow0ydl:
which angle is 90?
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Answered by
28
Thank you for asking this question. Here is your answer:
DC² = 28² – 9²
= 703
= 26.51 (DC)
Now we will find the area of ADC
s = ½(26.51+ 28 + 9) = 31.76
Area = √[ 31.76(31.76-26.51)( 31.76-28)( 31.76-9)]
= 119.45
Now we will find the area of ABC
s = ½(28+40+15) = 41.5
Area = √[ 41.5(41.5-28)( 41.5-15)( 41.5-40)]
= 149.23
So the total area is = 119.45 + 149.23
= 268.68 cm²
If there is any confusion please leave a comment below.
Answered by
1
Answer:
Step-by-step explanation:
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