Question

find the area of a quadrilateral in which AB = 9cm ,BC=40cm ,CD=28cm ,DA=15cm and ANGLE AB = 90 degree

Answer 1

Thank you for asking this question. Here is your answer:

DC² = 28² – 9²

= 703

= 26.51 (DC)

Now we will find the area of ADC

s = ½(26.51+ 28 + 9) = 31.76

Area = √[ 31.76(31.76-26.51)( 31.76-28)( 31.76-9)]

= 119.45

Now we will find the area of ABC

s = ½(28+40+15) = 41.5

Area = √[ 41.5(41.5-28)( 41.5-15)( 41.5-40)]

= 149.23

So the total area is = 119.45 + 149.23

= 268.68 cm²

If there is any confusion please leave a comment below.

Answer 2

Answer:

Step-by-step explanation: