Question

Find the area of a quadrilateral Park ABCD in which ab is equal to 26 BC is equal to 27 is equal to 78 is equal to 24 and angle d is equal to 90 degree solved question using heron's formula

Answer 1

Answer: please add root sign accordingly

And dont foregt to mark this as brainliest

Step-by-step explanation:

2S=5+4+3 ⇒ S=6

Area of ΔABC

=

s(s−a)(s−b)(s−c)

​

=

15(15−9)(15−8)(15−13)

​

=

6(1)(2)(3)

​

=

36

​

=6

⇒For area of ΔADC,

⇒2S=5+4+5

⇒ S=7cm

⇒Area of ΔADC

=

7(7−5)(7−5)(7−4)

​

=

7×2×2×3

​

=2

21

​

=9.16m

2

⇒Area of quad ABCD= Area of (△ABC+△ADC)

=6+9.16

=15.16 cm

2

≈15.2 cm

2