Question

Find the area of a quadrilateral PQRS in which <Q=90°,PQ=15cm, QR=36cm, RS=24cm and PS=21cm.{Answer In Detail}​

Answer 1

Answer:

$ac = \sqrt{{15}^{2}+{36}^{2}} \\ = 34$

answer is 5678

Step-by-step explanation:

please. Mark as brainliest

Answer 2

Given : QPS = 90 SQR = 90 PQ = 12 cm , PS = 9 cm , QR = 8 cm and SR = 17 cm By Pythagoras theorem in Δ SPQ we get : SP 2 + PQ 2 = SQ 2 92 + 122 = SQ2 ..