Find the area of a rectangle whose length and breadth are the roots of the quadratic equation x2 - 6x + 8 = 0
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Answered by
19
x^2 -6 x +8 = 0
(x -4)(x - 2) = 0
So ..lengh and breadth are 4 and 2...
Area of rectangle = 4×2 = 8 ....
(x -4)(x - 2) = 0
So ..lengh and breadth are 4 and 2...
Area of rectangle = 4×2 = 8 ....
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Construct a triangle with sides AB = 4cm, BC = 4.5cm, CA = 5cm, and also construct
another triangle with 2/3 of corresponding sides of ΔABC
another triangle with 2/3 of corresponding sides of ΔABC
Plz do dis also
If 1 and 2 are the zeros of the polynomid find x4
- 4x3
- 15x2
+ 58x - 40, find
other zeroes if any
- 4x3
- 15x2
+ 58x - 40, find
other zeroes if any
Plz
Answered by
4
x^2 - 6x + 8 = 0
x^2 - 4x - 2x + 8 = 0
x (x - 4) - 2(x - 4) = 0
(x-4)(x-2) = 0
x = 4 ; x = 2.
Area of rectangle = l*b = 4*2 = 8.
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