Question

Find the area of a rectangle whose length is 3/16 x^2y^3z and breadth is 4/21 z^3yx

Answer 1

Answer:

Area = (x³y⁴z⁴)/28

Explanation:

Dimensions of the rectangle:

Length = (3/16)x²y³z

Breadth = (4/21)z³yx

Area = Length × breadth

A = (3/16)x²y³z * (4/21)z³yx

= (3×4x³y⁴z⁴)/(16×21)

= (x³y⁴z⁴)/(4×7)

=(x³y⁴z⁴)/28

••••

Answer 2

Step-by-step explanation:

It is given that,

Length of a rectangle = 25 cm.

Breadth of a rectangle = 16 cm.

We know that,

Area of a rectangle = l∗b

Substituting the values,

=25∗16

=400cm

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