Find the area of a rectangle whose Perimeter is 64m and length is 20m
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Answered by
0
Answer:
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Step-by-step explanation:
Length of the rectangle = 20 m. So width of the rectangle = 32-20 = 12 m. So area of the rectangle = 20*12 = 240 sq m.
Answered by
1
Answer:
perimeter of recatnglle=2(l+b)
64=20+2b
2b=24
b=12
area of rectangle=l*b
=20*12=240
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