Find the area of a regular hexagon MNOPQR of side 5 cm.
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64cm^2
Step-by-step explanation:
We know that area of trapezium =
2
1
× sum of the parallel sides× distance between them
∴ area of trapezium MNQR=4×
2
11+5
=2×16=32 cm
2
So, the area of hexagon MNOPQR=2×32=64 cm
2
.
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