Question

FIND THE AREA OF A REGULAR PENTAGON ABCDE OF SIDES 4CM AND AD=BD=5CM.

Answer 1

Answer:

27.53 cm²

Step-by-step explanation:

To find the area of a regular pentagon, we apply the following formula

Formula:

$\boxed {\text{Area of Pentagon = }\frac{1}{4} \sqrt{5(5 + 2\sqrt{5} )} \ a^2}$

where a is the length of the side.

Given that the length of the side is 4cm:

$\text{Area = }\frac{1}{4} \sqrt{5(5 + 2\sqrt{5} )} \ (4)^2$

$\text{Area =} 27.53 \text{ cm}^2$