Question

find the area of a regular Pentagon whose each side is 5cm long and the radius of inscribed circle is 3.5cm​

Answer 1

$\huge\mathcal{Answer:}$

First find the area of one of the 5 isosceles triangles in the pentagon.

let side of pentagon a = 5cm

Perpendicular distance between centre of pentagon and the side = 3.5 cm

Area of the triangle = $\frac{1}{2} \times 5 \times 3.5$= 8.75 cm²

Therefore, area of pentagon

=8.75×5=43.75cm²