Find the area of a rhombous where each side measures 20 cm and one of its digonal is 32 cm .
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area of rombus = 1/2 ( product of diagonal )
given ,
side length =20 cm
one diagonal = 32 cm
let another diagonal is X
we know ,
relation between diagonal and side length of rohmbus
e.g.
(1 st diagonal)^2 + (2nd diagonal)^2 =4 (side length )^2
put given value ,
(32)^2 + (X)^2 =4 (20)^2
X^2 = 1600 - (32)^2 =1600-1024
= 576
X =24 cm
hence ,
area of rohmbus =1/2 (32 x 24) =16 x 24
=384 cm^2
given ,
side length =20 cm
one diagonal = 32 cm
let another diagonal is X
we know ,
relation between diagonal and side length of rohmbus
e.g.
(1 st diagonal)^2 + (2nd diagonal)^2 =4 (side length )^2
put given value ,
(32)^2 + (X)^2 =4 (20)^2
X^2 = 1600 - (32)^2 =1600-1024
= 576
X =24 cm
hence ,
area of rohmbus =1/2 (32 x 24) =16 x 24
=384 cm^2
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