Question

Find the area of a rhombus each side of which measures 20 cm and one of whose diagonals
is 24 cm.
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Answer 1

Answer:

Area of Rhombus : 1/2 *product of diagonals

imagine a rhombus D..........................C

                                  .            o             .

                                  .A..........................B

AO=OC=CB=BA=20cm−[side of rhombus]

AC=24cm

AO=  1/2×AC=  1/2×24=12cm−[originals of rhombus bisect each other]

∴ In right angled triangle AOD,

AD^2= AO^2+ OD^2(BY PYTHAGORAS THEOROM)

(20)  ^2= (12)^2 + OD^2

∴OD^2= 400 - 144

∴OD=√256

∴OD=16cm

∴OB=2×16=32cm

∴ Area of rhombus=1/2 *PRODUCT OF DIAGONALS

=1/2 *32*24=384cm^2

FINAL ANSWER = 384cm^2

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Step-by-step explanation: