find the area of a rhombus having each side equal to 13cm and one of the diagonal equal to 24cm
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The diagonals perpendicular to each other. and half of it forms a right angle triangle with the side. let the unknown half of the diagonal be x.
then x² = 13²-12²= 25. therefore x= 5. Then length of other diagonal = 2 *5 =10
The area of rombus= 1/2 × product of diagonals.= 0.5 *10 * 24= 120 cm².
I Hope my answer is clear
then x² = 13²-12²= 25. therefore x= 5. Then length of other diagonal = 2 *5 =10
The area of rombus= 1/2 × product of diagonals.= 0.5 *10 * 24= 120 cm².
I Hope my answer is clear
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kritika53:
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