Question

Find the area of a rhombus having perimetre 40 cm. and diagonal 16 cm.
=96​

Answer 1

Answer:

Step-by-step explanation:

one side can be calculated by dividing 40 by 4 i.e 10 . and after that we know that diagonals bisects each other at 90° , so there froms a right angled triangle in hypotenuse will be the side and one side be 16/2 i.e 8 and after that third side will be calculated by Pythagoras theorem and after that area can be calculated by the formula 1/2 × base ×height

Answer 2

Answer

$Perimeter of Rhombus = 40cm\\One diagonal = 16 cm\\Therefore\\4* side = 40\\Side = 10 cm\\\\So by heron's formulaS = 16 + 10 + 10 /2 = 18\\18 ( 18 - 16 ) ( 18 - 10 ) ( 18 - 10 )\\= 18 * 2 * 8 * 8\\= 8 2 * 3 * 3 * 2= 8 * 2 * 3\\= 48 sq cmArea of one triangle = 48\\Area of two triangles = 48 * 2 = 96 sq cm\\Area of rhombus = 96 sq cm$

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