find the area of a rhombus having sides equal to 13 cm and one of its diagonal 10 cm
Answers
Answered by
2
It's formula is
p=diagonals
Q=side
Area = pq/2
=10*13/2
=5*13
=65
p=diagonals
Q=side
Area = pq/2
=10*13/2
=5*13
=65
living36:
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Answered by
1
Answer:
13sq-25sq=144=12sq
So l of other diagonal is 2*12=24
So ar =1/2 *24*10
=120
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