Question

Find the area of a rhombus if its diagonals are 18 cm and 19 cm.​

Answer 1

Question:

Find the area of a rhombus if its diagonals are 18 cm and 19 cm.​

Subject:

Maths

Topic :

Area of Rhombus

Given:

In Rhombus ABCD the diagonals of a rhombus are  AC = 18 cm and BD =  19 cm respectively

Figure:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,0){\line(1,3){1.5}}\put(0,0){\line(1,0){5}}\put(5,0){\line(1,3){1.5}}\put(1.5,4.5){\line(1,0){5}}\qbezier(1.56,4.5)(1.56,4.5)(5,0)\qbezier(6.45,4.5)(6.45,4.5)(0,0)\put(-0.5,-0.5){\sf B}\put(1,4.8){\sf A}\put(5.2,-0.5){\sf C}\put(6.7,4.75){\sf D}\put(3,1.6){\sf O}\end{picture}$

To Find:

The Area of the Rhombus

Formula Used:

$\frac{1}{2}\times d_{1} \times d_2$

Solution:

Diagonal AC = $d_1$

Diagonal BD = $d_2$

Area of the Rhombus = $\frac{1}{2}\times d_{1} \times d_2$

$\frac{1}{2}\times18\times 19\\\\\\\frac{9}1\times19\\\\\\9\times19\\\\\\=171cm^2\\\\\\\boxed{=171cm^2}$

Answer:

Area of the Rhombus = 171 cm²

Extra Information:

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \end {minipage}}$

Be Brainly!

Answer 2

Step-by-step explanation:

your correct answer is 171 CM square