Question

find the area of a rhombus in which each side is 15 cm long and one of whose diagonal is 24 cm

Answer 1

HERE IS YOUR ANSWER.....!!!!


In rhombus ABCD
AB=BC=CD=AD=15cm
Let AC = 24cm
AO=1/2AC [in rhombus diagonals bisect each other]
=1/2 * 24
AO = 12cm

Consider triangle AOB
${ab}^{2} = \: {ao \: }^{2} + {bo}^{2}$
BO² = AB² -- AO²
= 15² -- 12²
= 225 - 144
BO²= 81
BO = 9cm

BD= 2BO
therefore , BD = 18 cm


area(rhombus ABCD) = 1/2 * diagonal¹ * diagonal²
= 1/2 * 24 * 18
= 216cm²




Hope it helps

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Answer 2

The answer is 216cm×cm
first one diagonal is given 24cm, so diagonals of rhombus bisect each other...... and sides are also given
Now it makes 4 triangles
use Pythagoras theorem..... then you will get the half value of another diagonal...
the value multiple by 2 then you will get the full value of diagonal...
Now you use the formula of area of rhombus.... then you will get your answer.......
answer is 216