find the area of a rhombus in which each side is 15 cm long and one of whose diagonal is 24 cm
Answers
Answered by
1
I think the answer is
1/2*24*18 = 12*18 = 216cm sq.
Area of Rhombus = 1/2*product of two
diagonals
1/2*24*18 = 12*18 = 216cm sq.
Area of Rhombus = 1/2*product of two
diagonals
Answered by
13
Solutions :-
Given :
Side of Rhombus = a = 15 cm
One of its Diagonal = q = 24 cm
Find the area of a rhombus :-
We know that,
Area of Rhombus = ½ q √(4a²﹣q²) sq. units
= ½ × 24 √(4 × 15²﹣24²) cm²
= 12 √(900﹣576) cm²
= 12 √324 cm²
= 12 × 18 cm²
= 216 cm²
Hence,
Area of Rhombus = 216 cm²
Given :
Side of Rhombus = a = 15 cm
One of its Diagonal = q = 24 cm
Find the area of a rhombus :-
We know that,
Area of Rhombus = ½ q √(4a²﹣q²) sq. units
= ½ × 24 √(4 × 15²﹣24²) cm²
= 12 √(900﹣576) cm²
= 12 √324 cm²
= 12 × 18 cm²
= 216 cm²
Hence,
Area of Rhombus = 216 cm²
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