Math, asked by kridonmonalR, 1 year ago

Find the area of a rhombus , the lengths of whose diagonals are 16cm and 24 cm respectively

Answers

Answered by pahiroy1221
140
it is given that ,
length of 1st diagonal = 16 cm
length of 2nd diagonal = 24 cm
area of rhombus = diagonal 1 * diagonal 2/2

therefore area is,
= 16*24/2
= 8*24
= 192 cm^2
so the answer is 192cm^2 which is the area of the given rhombus.
 i hope that this will help u....................^_^
Answered by Jahnvi97
115
Length of diagonals = 16cm and 24cm

Area of rhombus = 1/2 * (product of diagonals)
⇒ A = 1/2(16*24)
⇒ A = (16*24)÷2
⇒ A = 16*12
⇒ A = 192 cm²

Area is 192cm²
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