Find the area of a rhombus , the lengths of whose diagonals are 16cm and 24 cm respectively
Answers
Answered by
140
it is given that ,
length of 1st diagonal = 16 cm
length of 2nd diagonal = 24 cm
area of rhombus = diagonal 1 * diagonal 2/2
therefore area is,
= 16*24/2
= 8*24
= 192 cm^2
so the answer is 192cm^2 which is the area of the given rhombus.
i hope that this will help u....................^_^
length of 1st diagonal = 16 cm
length of 2nd diagonal = 24 cm
area of rhombus = diagonal 1 * diagonal 2/2
therefore area is,
= 16*24/2
= 8*24
= 192 cm^2
so the answer is 192cm^2 which is the area of the given rhombus.
i hope that this will help u....................^_^
Answered by
115
Length of diagonals = 16cm and 24cm
Area of rhombus = 1/2 * (product of diagonals)
⇒ A = 1/2(16*24)
⇒ A = (16*24)÷2
⇒ A = 16*12
⇒ A = 192 cm²
Area is 192cm²
Area of rhombus = 1/2 * (product of diagonals)
⇒ A = 1/2(16*24)
⇒ A = (16*24)÷2
⇒ A = 16*12
⇒ A = 192 cm²
Area is 192cm²
Similar questions