Question

Find the area of a rhombus whose one diagonal is 8cm and other diagonal is 6cm.​

Answer 1

Answer:

24cm²

Step-by-step explanation:

Area of rhombus  is 1/2 x D1 xD2

=1/2x48=24cm²

Answer 2

Correct Question-:

• Find the area of a rhombus whose one diagonal is 8cm and other diagonal is 6cm.

AnswEr-:

• $\implies{\sf{\large {Area\:of\:Rhombus\: = \: 24cm² }}}$

EXPLANATION-:

• $\frak{Given \:\: -:} \begin{cases} \sf{The\:Diagonal_{1} \:of\:Rhombus \:\:is\:= \frak{8cm}} & \\\\ \sf{The\:Diagonal_{2} \:of\:Rhombus \:\:is\: \:=\:\frak{6cm}}\end{cases}$
• $\frak{To \:Find\: -:} \begin{cases} \sf{The\:Area\:of\:Rhombus \:.\:}\end{cases}$

Solution -:

• $\underline{\boxed{\star{\sf{\blue{ Area \:of\:Rhombus\:is\: \: =\frak{\frac{1}{2}× Diagonal _{1}Diagonal _{2}}\:.}}}}}$

• $\frak{Here \:\: -:} \begin{cases} \sf{The\:Diagonal_{1} \:of\:Rhombus \:\:is\:= \frak{8cm}} & \\\\ \sf{The\:Diagonal_{2} \:of\:Rhombus \:\:is\: \:=\:\frak{6cm}}\end{cases}$

Now,

• $\implies{\sf{\large {Are_{(Rhombus)}\: = \: frac{1}{2}× 8 × 6 }}}$
• $\implies{\sf{\large {Are_{(Rhombus)}\: = \: 4 × 6 }}}$
• $\implies{\sf{\large {Are_{(Rhombus)}\: = \: 24cm² }}}$

Therefore,

• $\implies{\sf{\large {Are_{(Rhombus)}\: = \: 24cm² }}}$

Hence ,

• $\implies{\sf{\large {Area\:of\:Rhombus\: = \: 24cm² }}}$

☆ Figure of Rhombus-:

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,0){\line(1,3){1.5}}\put(0,0){\line(1,0){5}}\put(5,0){\line(1,3){1.5}}\put(1.5,4.5){\line(1,0){5}}\qbezier(1.56,4.5)(1.56,4.5)(5,0)\qbezier(6.45,4.5)(6.45,4.5)(0,0)\put(-0.5,-0.5){\sf B}\put(1,4.8){\sf A}\put(5.2,-0.5){\sf C}\put(6.7,4.75){\sf D}\put(3,1.6){\sf O}\end{picture}$

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♤ More To Know ♤

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

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♡ Note -:

• Please see this answer in website of brainly . [ Brainly.in]

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