Question

Find the area of a rhombus whose one side is 8 cm and height is 6 cm . ​

Answer 1

❏GIVEN:

➠One Side is =8cm

➠Height is=6cm

❏TO FIND:

➠Area of rhombus=?¿

❏Formula Used:

➠Area of rhombus =Breadth × Height

❏Procedure:

Convert deci- metre to cm

$\fbox \pink{1dm = 10cm}$

➠So, 0.8 dm will be 18×0.8

➠8cm

We know are of rhombus is Breadth × Height

So,

$Area = 8cm \times 8cm \\ {64cm}^{2}$

➠MORE APPROACHES TO FIND AREAS OF DIFFERENT FIGURES↷

1/2 Base × Height= Area of Triangle

Length × Breadth = Rectangles Area

HOPE IT HELPS U! :)

Answer 2

Given:-

• One side of the rhombus is 8 cm.
• Height of the rhombus is 6 cm.

⠀

To find:-

• Area of the rhombus.

⠀

Solution:-

★Formula used:-

$\star{\boxed{\sf{\orange{Area\: of\: rhombus = base \times height}}}}$

⠀

$\tt\longmapsto{b \times h}$

⠀

$\tt\longmapsto{8 \times 6}$

⠀

$\tt\longmapsto{\boxed{\red{48\: cm^2}}}$

⠀

Hence,

• the area of the rhombus is 48 cm².

⠀

★More to know :-

$\sf{Area\;of\;Rectangle\;=\;Length\;\times\;Breadth}$

⠀

$\sf{Area\;of\;Square\;=\;(Side)^{2}}$

⠀

$\sf{Area\;of\;Triangle\;=\;\dfrac{1}{2}\;\times\;Base\;\times\;Height}$

⠀

$\sf{Area\;of\;Parallelogram\;=\;Base\;\times\;Height}$

⠀

$\sf{Area\;of\;Circle\;=\;\pi r^{2}}$

$\sf{Perimeter\;of\;Rectangle\;=\;2\;\times\;(Length\;+\;Breadth)}$

⠀

$\sf{Perimeter\;of\;Rectangle\;=\;4\;\times\;(Side)}$

⠀

$\sf{Perimeter\;of\;Circle\;=\;2\pi r}$